Mathematics

\[(a+b)^2 = a^2 + 2ab + b^2\]

\[(a-b)^2 = a^2 - 2ab + b^2\]

\[\frac{b^2 \pm \sqrt{b^2 - 4ac}}{2a}\]

\[sin^{-1}{\left(\frac{O}{H}\right)} = \theta\]

Note

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